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If h is vertical height, b=horizontal distance from wall to bottom of ladder and l=lenght of ladder,we can say lsquared = hsquared + b squared. Now differentiate w.r.t. time t. 2l*dl/dt= 2h* dh/dt + 2b*db/dt =0 However this solution doesn't give exactly the same answer when one solves the problem geometrically or using simple pythagorus. For example ,if l=20m and b=12 m and h=16m and db/dt is 2m/s, I calculate dh/dt as !.5 m/s using calculus but 1.717 m/s using geometry or straight Pythagorus. Where is the fallasy inthe method using calculus? Ray Bevan
Oh honey, we've got ourselves a classic right triangle situation here. Using some good ol' trigonometry, you can find that the angle between the ladder and the ground is approximately 83 degrees. Just remember, math may not be your friend, but it's definitely not your enemy either.
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