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A line has x-intercept 5 comma 0 and is perpendicular to the line 2x plus 8y equals 10 Find the y-intercept of the line?
Wiki User
∙ 13y ago
L1: x-intercept point (5, 0), perpendicular to L2
L2: 2x + 8y = 10
2x + 8y = 10
8y = -2x + 10
y = (-2/8)x + 10/8
y = -(1/4)x + 5/4, m2 = -1/4 so that m1 = 4
y = mx + b, replace y with 0, m with 4, and x with 5
0 = 4(5) + b
0= 20 + b subtract 20 from both sides
-20 = b, the y-intercept of L1.
Wiki User
∙ 13y ago
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