The slope of the line represented by the equation y = 3x - 2 is 3. The slope of the line perpendicular to y = 3x - 2 must be -1/3.
Since the slope = rise/run = - 1/3, we can find other points of that vertical line such as:
(0 - 3, 6 +1) = (-3, 7) which is above the point (0, 6)or
(0 + 3, 6 - 1) = (3, 5) which is below the point (0, 6).
In the same way we can find other points.
Perpendicular lines passing through a point are at right angles to each other.
No, because a slope needs to be negative and opposite the other slope to be perpendicular and in this problem it is not.
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin
The origin and infinitely many other points of the form (x, ax) where x is any real number.
-1
Perpendicular lines passing through a point are at right angles to each other.
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Perpendicular to 2x - 3y = 8 through the point ( 2, 1 ) (Perpendicular means the slopes are negative inverses of each other) 3x+2y = 8
TRUE:: The first two lines lie in the same plain, but are perpendicular to each other. The third line passes through the plane of the first two lines so it is also perpendicular. Think 3-dimension. !!!!!
No, because a slope needs to be negative and opposite the other slope to be perpendicular and in this problem it is not.
It is perpendicular to a family of other linear equations: of the form 4y = x + c
No but y = -1/2x+3 is perpendicular to y = 2x+6
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
The origin and infinitely many other points of the form (x, ax) where x is any real number.
-1
You have to know the slopes of both lines. -- Take the two slopes. -- The lines are perpendicular if (one slope) = -1/(the other slope), or the product of the slopes equals to -1.