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A motorcycle traveling at 15 meters per second accelerates at a constant rate of 4.0 meters per second squared over a distance of 50 meter.how long does it cover 50m distance?
Wiki User
∙ 14y ago
D = V0 t + 1/2 A t2
50 = 15 + 1/2 (4) t2
35 = 2 t2
t = sqrt(35/2) = sqrt(17.5) = 4.183 seconds (rounded)
Wiki User
∙ 14y ago
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A motorcycle traveling at 15 m s accelerates at a constant rate of 4.0 ms over a distance of 50 meters What is the final velocity of the motorcycle?
25 m/s
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# A car is traveling at a constant velocity with magnitude . At the instant that the car passes a motor cycle officer, the motor cycle accelerates from rest with acceleration . # ## Sketch an graph of the motion of both objects. Show that when the motor cycle overtakes the car, the motorcycle has a speed twice that of the car, no matter what the value of . ## Let be the distance the motorcycle travels before catching up with the car. In terms of , how far has the motorcycle traveled when its velocity equals the velocity of the car?
How long would it to do 84 miles traveling 50mph?
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For a car traveling at a constant rate of 60 mph the distance traveled is a function of the time traveled. how do i express this relation as a function?
D = 60T where T is expressed in hours.
Does perpendicular lines have a constant distance between them?
No but parallel lines have a constant distance between them
A motorcycle traveling at 15 m s accelerates at a constant rate of 4.0 ms over a distance of 50 meters What is the final velocity of the motorcycle?
25 m/s
4 A car is traveling at a constant velocity with magnitude At the instant that the car passes a motor cycle officer the motor cycle accelerates from rest with acceleration a Sketch an grap?
# A car is traveling at a constant velocity with magnitude . At the instant that the car passes a motor cycle officer, the motor cycle accelerates from rest with acceleration . # ## Sketch an graph of the motion of both objects. Show that when the motor cycle overtakes the car, the motorcycle has a speed twice that of the car, no matter what the value of . ## Let be the distance the motorcycle travels before catching up with the car. In terms of , how far has the motorcycle traveled when its velocity equals the velocity of the car?
When an object is traveling the same distance every second it has a?
constant speed
A motorcycle accelerates from 15 ms to 20 ms over a distance of 50 meters. What is its average acceleration?
1.75 m/s^2
A car traveling at 15 m s accelerates to 35m s covering distance of 80 meters what was the acceleration rate?
It was 6.25 ms^-2
The distance traveled by an automobile moving at a constant velocity is?
(Its speed) x (time it spends traveling).
Does a car traveling the logest time always travels the gratest distance?
Not necessarily. The distance a car travels is determined by its speed and the time it spends traveling. If a car is traveling at a slower speed but for a longer period of time, it may not cover as much distance as a car traveling at a faster speed but for a shorter period of time. So, the longest time does not always correspond to the greatest distance traveled.
Does the car traveling the longest time travel the greatest distance?
No. In general, for the simplified case of constant speed, use the formula: distance = speed x time
Does the car traveling the longest time always travel the greatest distance?
No. In general, for the simplified case of constant speed, use the formula: distance = speed x time
How long would it to do 84 miles traveling 50mph?
The formula for constant speed is: distance = speed x time Solving for time, it turns out that you simply have to divide distance by speed.
HOW NG WILL IT TAKE TO TRAVEL 180 MILES TRAVELING AT 100 MILES PER HOUR?
The standard formula for constant speed problems: distance = speed x time In this case, you need to divide the distance by the speed.
Can the distance traveled still be divided by the time taken to travel the distance if the speed accelerates to travel the distance?
The formula, distance = speed x time, or speed = distance / time, assumes constant speed. If the speed changes, then the formula speed = distance / time will give you the average speed over the time period. To get the instantaneous speed in this case, you must divide distance / time for a very short time interval.
