Best Answer

Ratio of new length to old length = 12/8 = 3/2

So ratio of new width to old width must be 3/2

New width/Old width = 3/2 so New width = Old Width * 3/2 = 6 inches*3/2 = 9 inches

Q: A picture 8 inches long of 6 inches width is to be enlarged so that its length will be 12 inches what is the width in inches of the enlarged picture?

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24 inches

The length is 7 inches and the width is 5 inches for a envelope

It is 2*(9+5) = 2*14 = 28 inches.

61 inches and 18 inches.

The width is expressed in inches.

Related questions

9 inches7.5 inches wide

Then the width has to be 9 in

2/1

The width of a rectangle is the shorter measurement and length is the longer. So in the case of the picture frame, 6 inches would be the width, and 10 inches would be the length.

The width is 9 inches because the scale factor from 8 to 12 is 1.5 so 6 multiplied by 1.5 is 9.

24 inches

The length is 7 inches and the width is 5 inches for a envelope

The length of the Murcielago is 181 inches, and the width is 81 inches.

The picture has a perimeter of 22. If the width is 5 and the length is 6, which is in compliance with the parameters of the question, then 5+5+6+6=22.

Width = 9 inches Length = 30 inches

You multiply the width by the length to get the area. In this case the answer would be 1,080 square inches.

It is 2*(9+5) = 2*14 = 28 inches.