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Width = 9 inches

Length = 30 inches

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Q: The length of a rectangle is 3 inches more than three times the width The perimeter is 78 inches Find the length and width?
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The length of a rectangle is equal to three times its width if the perimeter is equal to 40 feet what is the length of the rectangle?

15 feet.


He length of a rectangle is three times its width. If the area of the rectangle is 192 m2 find its perimeter.?

64 meters


The perimeter of a rectangle is 22 ft a right triangle inside the rectangle has a perimeter of 12 ft it's hypotenuse is 5 ft one side of the triangle is half the length of the rect solve all length?

ok, i figured it out. the length of the triangle is 5, 4, 3. the four is 1/2 the length of one side of the rectangle. so the rectangle sides are 8, 8, 3, 3 (one three being one side of the rectangle as well)


The length of a rectangle is three times its width If the area of the rectangle is 147 what is its perimeter?

Write a a series of equations as follows p=2l+2w (formula for perimeter) a=l*w (Formula for area) l=3w (fact given in the question) a=147 (fact given in hte question) We don't currently have enough information to solve the perimeter formula for this rectangle, so we begin with the area formula to get more information. By substituteing 147 for the variable a and 3w for the variable l, we arrive at this equation: 147=w*3w With only one variable, we can solve this equation by isolating w on one side as follows 147=3w2(Multiply w by w to combine like terms) 147/3=3w2/3 (divide both sides by 3) 49=w2 sqrt49=sqrtw2(square root of both sides) 7=w We now know that the width of the rectangle is 7. We also know that the length is three times that, which is 21. We can substitute these values into the perimeter eequation as follows: p=(2*7)+(2*21) p=14+42 p=56 The perimeter of the rectangle is 56


If the perimeter of a rectangle is 64 cm and the length is three times its width what is the area?

Let x = width of the box. We know that the length = 3x, and that the perimeter is 2*length + 2*width, thus we have the equation 2*(3x) + 2*x = 64 => 6x+2x = 64 Combining like terms: => 8x = 64 Solving for x by dividing both sides by 8: x=8 Thus we know that the width is 8, and length = 3*x =3*8 = 24 Area = width*length = 8*24 = 192

Related questions

If the perimeter of a rectangle is twenty four inches find the dimensions if its length is three times the height.?

That would be 3 x 9 inches.


A rectangle has length three time its width if the perimeter of the rectangle is 56 inches what is the length of the rectangle?

l=3w Perimeter (p) = 2*(l+w) = 56 2*(3w+w)=56 2*4w=56 8w=56 w=7 inches l=3w = 3*7 = 21 inches


The length of a rectangle is three times its width If the perimeter of the rectangle is 486in2 what is its area?

the length is equal to 160,083


The length of a rectangle is equal to three times its width if the perimeter is equal to 40 feet what is the length of the rectangle?

15 feet.


The length of a rectangle is equal to three times its width if the perimeter is equal to 168 feet what is the length of the rectangle?

63 feet


A rectangle has a length three times its width The perimeter is 68?

Width: 8.5 Length: 25.5


A rectangle has a length three times its width The perimeter is 72 inches sketch the rectangle the rectangle and then calculate its dimensions?

The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.


What is an expression for the perimeter of a rectangle that has a length which is three times its width?

call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x


The length of a rectangle is three times the width. The perimeter is 96 cm. Find the width and length?

dont is answer


He length of a rectangle is three times its width. If the area of the rectangle is 192 m2 find its perimeter.?

64 meters


The perimeter of a rectangle is 28 inches if the length of the rectangle is three inches more than three times the width find the dimensions?

L + W = 28/2 = 14 L = 3 + 3W, so 3 + 3W + W = 14 ie 4W = 11 so width is 2¾" and length is 11¼"


The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?

Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2