Best Answer

From your description, I get:

a + b + c = 180b - 3a

c = 5a

You have two equations and three unknowns, which is unsolvable.

Q: A plus b plus c equals 180 b-3a and c equals 5a what the answer to c?

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a = 20 b = 60 c = 100

Gathering like terms together, this can be rewritten: 9a = 180 Dividing both sides of the equation by 9: a = 20

2a+5a+9a = 16a

a = 0

A= 2

Related questions

a + 3a + 5a = 180 9a =180 a = 20

a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100

Divide 5a and 180 by 5. a = 36

a = 20 b = 60 c = 100

Gathering like terms together, this can be rewritten: 9a = 180 Dividing both sides of the equation by 9: a = 20

2a+5a+9a = 16a

5a+5=6a-7

Answer to: 5a + 1 = a - 3a = -1

a = 0

7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2

The statement is false. 5a +6 = 5a + 30 Subtract 5a from both sides: 6 = 30 and that is plain and simple rubbish!

A= 2