a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
2a + 3a = 5a
The given expression can be simplified to: 3b-a
-8a + 3a = (-8 + 3)a = (5)a = 5a
3a + 2a = 5a
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
From your description, I get: a + b + c = 180b - 3a c = 5a You have two equations and three unknowns, which is unsolvable.
a = 20 b = 60 c = 100
Answer to: 5a + 1 = a - 3a = -1
Gathering like terms together, this can be rewritten: 9a = 180 Dividing both sides of the equation by 9: a = 20
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
2a + 3a + 4 = 5a + 4
12a
a is equal to 4
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
1a (or just a for short).
2a + 5a + 3a = 10a