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A population has mean 128 and standard deviation 22. find the mean and the standard deviation of mean for sample of size 36?
The mean of the sample means remains the same as the population mean, which is 128. The standard deviation of the sample means, also known as the standard error, is calculated by dividing the population standard deviation by the square root of the sample size. Therefore, the standard error is ( \frac{22}{\sqrt{36}} = \frac{22}{6} \approx 3.67 ). Thus, the mean is 128 and the standard deviation of the sample means is approximately 3.67.
What else can I help you with?
How do you find the sample deviation?
You're an idiot. It's standard deviation. Google that for your answer.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
What is the probability that a sample of 120 female graduates will provide a sample mean more than .30 below the population mean?
To determine the probability that a sample mean from 120 female graduates is more than 0.30 below the population mean, you would need information about the population standard deviation or the standard error of the sample mean. Assuming a normal distribution, you can use the Central Limit Theorem to find the standard error by dividing the population standard deviation by the square root of the sample size (120). Then, you can calculate the z-score corresponding to a sample mean that is 0.30 below the population mean and use a standard normal distribution table or calculator to find the probability associated with that z-score.
Population has a mean of and micro80 and standard deviation of and sigma10. If a sample is taken from the population with a sample size of and 57345 25 find the percentage that the sample mean is samp?
To find the percentage that the sample mean is within a certain range, we can use the Central Limit Theorem. Given a population mean (μ) of 80 and a standard deviation (σ) of 10, for a sample size (n) of 25, the standard error (SE) is calculated as σ/√n = 10/√25 = 2. To find the percentage of sample means that fall within a specific range, you would use the z-score formula and standard normal distribution tables. However, without specifying the range for the sample mean, we cannot provide a specific percentage.
What Percent of population between 1 standard deviation below the mean and 2 standard deviations above mean?
In a normal distribution, approximately 68% of the population falls within one standard deviation of the mean, and about 95% falls within two standard deviations. Therefore, to find the percentage of the population between one standard deviation below the mean and two standard deviations above the mean, you would calculate 95% (within two standard deviations) minus 34% (the portion below one standard deviation), resulting in approximately 61% of the population.
How do i find sample standard deviation from population standard deviation?
If the population standard deviation is sigma, then the estimate for the sample standard error for a sample of size n, is s = sigma*sqrt[n/(n-1)]
How do you find the sample deviation?
You're an idiot. It's standard deviation. Google that for your answer.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
What is the probability that a sample of 120 female graduates will provide a sample mean more than .30 below the population mean?
To determine the probability that a sample mean from 120 female graduates is more than 0.30 below the population mean, you would need information about the population standard deviation or the standard error of the sample mean. Assuming a normal distribution, you can use the Central Limit Theorem to find the standard error by dividing the population standard deviation by the square root of the sample size (120). Then, you can calculate the z-score corresponding to a sample mean that is 0.30 below the population mean and use a standard normal distribution table or calculator to find the probability associated with that z-score.
How do you find the sample size when given the standard deviation and the mean with a sample value?
You cannot from the information provided.
Population has a mean of and micro80 and standard deviation of and sigma10. If a sample is taken from the population with a sample size of and 57345 25 find the percentage that the sample mean is samp?
To find the percentage that the sample mean is within a certain range, we can use the Central Limit Theorem. Given a population mean (μ) of 80 and a standard deviation (σ) of 10, for a sample size (n) of 25, the standard error (SE) is calculated as σ/√n = 10/√25 = 2. To find the percentage of sample means that fall within a specific range, you would use the z-score formula and standard normal distribution tables. However, without specifying the range for the sample mean, we cannot provide a specific percentage.
If quartile deviation is 24. find mean deviation and standard deviation?
Information is not sufficient to find mean deviation and standard deviation.
How do you determine your sample score on the comparison distribution?
To determine your sample score on the comparison distribution, you first need to calculate the sample mean and standard deviation. Then, you can use these statistics to find the z-score, which indicates how many standard deviations your sample mean is from the population mean. By comparing this z-score to critical values from the standard normal distribution, you can assess the significance of your sample score in relation to the comparison distribution.
A recent survey of 50 executives who were laid off from their previous position revealed it took a mean of 26 weeks for them to find anoher positio the standard deviation of the sample was 6.2 weeks?
A recent survey of 50 executives who were laid off from their previous position revealed it took a mean of 26 weeks for them to find anoher positio. the standard deviation of the sample was 6.2 weeks. construct a 95 % confidence interval for the population. Is it reasonable that the population mean is 28 weeks? Justify your answer
What Percent of population between 1 standard deviation below the mean and 2 standard deviations above mean?
In a normal distribution, approximately 68% of the population falls within one standard deviation of the mean, and about 95% falls within two standard deviations. Therefore, to find the percentage of the population between one standard deviation below the mean and two standard deviations above the mean, you would calculate 95% (within two standard deviations) minus 34% (the portion below one standard deviation), resulting in approximately 61% of the population.
How do you calculate standard deviation without a normal distribution?
You calculate standard deviation the same way as always. You find the mean, and then you sum the squares of the deviations of the samples from the means, divide by N-1, and then take the square root. This has nothing to do with whether you have a normal distribution or not. This is how you calculate sample standard deviation, where the mean is determined along with the standard deviation, and the N-1 factor represents the loss of a degree of freedom in doing so. If you knew the mean a priori, you could calculate standard deviation of the sample, and only use N, instead of N-1.
The Empirical Rule indicates that we can expect to find what proportion of the sample included within plus or and - 2 standard deviation?
The proportion is approx 95%.
