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A population has mean 128 and standard deviation 22. find the mean and the standard deviation of mean for sample of size 36?
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How do you find the sample deviation?
You're an idiot. It's standard deviation. Google that for your answer.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
How do you calculate standard deviation without a normal distribution?
You calculate standard deviation the same way as always. You find the mean, and then you sum the squares of the deviations of the samples from the means, divide by N-1, and then take the square root. This has nothing to do with whether you have a normal distribution or not. This is how you calculate sample standard deviation, where the mean is determined along with the standard deviation, and the N-1 factor represents the loss of a degree of freedom in doing so. If you knew the mean a priori, you could calculate standard deviation of the sample, and only use N, instead of N-1.
The Empirical Rule indicates that we can expect to find what proportion of the sample included within plus or and - 2 standard deviation?
The proportion is approx 95%.
How to calculate variance of 3 5 6 4 7 7 8?
To calculate variance, (population standard deviation squared), usually written as σ2, first find the mean. In this case, ( 3 + 5 + 6 + 4 + 7 + 7 +8 ) / 7 = 40/7 ≈ 5.7143 Then find the difference between every number and the mean. 5.7143 - 3 = 2.7143 5.7143 - 5 = 0.7143 5.7143 - 6 = -0.2857 5.7143 - 4 = 1.7143 5.7143 - 7 = -1.2857 5.7143 - 7 = -1.2857 5.7143 - 8 = -2.2857 Then square all of the differences. 7.3674 0.5102 0.0816 2.9388 1.6530 1.6530 5.2244 Then add the products together. 19.4284 Then divide by the number of numbers in the set of data (7) for the variance. σ2 ≈ 2.78 Since you are using the entire population, you use the population standard deviation instead of the sample standard deviation. In statistics, you are more likely to see sample standard deviation, but since there are only seven numbers in the data set, we use the population standard deviation.
How do i find sample standard deviation from population standard deviation?
If the population standard deviation is sigma, then the estimate for the sample standard error for a sample of size n, is s = sigma*sqrt[n/(n-1)]
How do you find the sample deviation?
You're an idiot. It's standard deviation. Google that for your answer.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
How do you find the sample size when given the standard deviation and the mean with a sample value?
You cannot from the information provided.
If quartile deviation is 24. find mean deviation and standard deviation?
Information is not sufficient to find mean deviation and standard deviation.
A recent survey of 50 executives who were laid off from their previous position revealed it took a mean of 26 weeks for them to find anoher positio the standard deviation of the sample was 6.2 weeks?
A recent survey of 50 executives who were laid off from their previous position revealed it took a mean of 26 weeks for them to find anoher positio. the standard deviation of the sample was 6.2 weeks. construct a 95 % confidence interval for the population. Is it reasonable that the population mean is 28 weeks? Justify your answer
How do you calculate standard deviation without a normal distribution?
You calculate standard deviation the same way as always. You find the mean, and then you sum the squares of the deviations of the samples from the means, divide by N-1, and then take the square root. This has nothing to do with whether you have a normal distribution or not. This is how you calculate sample standard deviation, where the mean is determined along with the standard deviation, and the N-1 factor represents the loss of a degree of freedom in doing so. If you knew the mean a priori, you could calculate standard deviation of the sample, and only use N, instead of N-1.
Why we calculate standard deviation and quartile deviation?
we calculate standard deviation to find the avg of the difference of all values from mean.,
The Empirical Rule indicates that we can expect to find what proportion of the sample included within plus or and - 2 standard deviation?
The proportion is approx 95%.
Is variance the square root of standard deviation?
No, you have it backwards, the standard deviation is the square root of the variance, so the variance is the standard deviation squared. Usually you find the variance first, as it is the average sum of squares of the distribution, and then find the standard deviation by squaring it.
How to calculate variance of 3 5 6 4 7 7 8?
To calculate variance, (population standard deviation squared), usually written as σ2, first find the mean. In this case, ( 3 + 5 + 6 + 4 + 7 + 7 +8 ) / 7 = 40/7 ≈ 5.7143 Then find the difference between every number and the mean. 5.7143 - 3 = 2.7143 5.7143 - 5 = 0.7143 5.7143 - 6 = -0.2857 5.7143 - 4 = 1.7143 5.7143 - 7 = -1.2857 5.7143 - 7 = -1.2857 5.7143 - 8 = -2.2857 Then square all of the differences. 7.3674 0.5102 0.0816 2.9388 1.6530 1.6530 5.2244 Then add the products together. 19.4284 Then divide by the number of numbers in the set of data (7) for the variance. σ2 ≈ 2.78 Since you are using the entire population, you use the population standard deviation instead of the sample standard deviation. In statistics, you are more likely to see sample standard deviation, but since there are only seven numbers in the data set, we use the population standard deviation.
We have a population with mean of 100 and standard deviation of 28 take repeated samples of size 49 and calculate the mean of each sample to form a sampling distribution Is it a Normal Distribution?
a) T or F The sampling distribution will be normal. Explain your answer. b) Find the mean and standard deviation of the sampling distribution. c) We pick one of our samples from the sampling distribution what is the probability that this sample has a mean that is greater than 109 ? Is this a usual or unusual event? these are the rest of the question.
