answersLogoWhite

0


Best Answer

15.42 degrees

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: A projectile is fired in such a way that its horizontal range is equal to 14.5 times its maximum height What is the angle of projection?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

The angle of projection of a projectile for which the horizontal range and maximum height are equal?

45 degrees.


What is the factor influence the distance and time in projectile motion?

projection speed projection angle projection height


What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?

The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.


Which is the total velocity of a projectile at maximum height?

It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.


In the oblique projection a projectile reaches the maximum height in 8 seconds it is time of flight is?

If a projectile takes 8 seconds to reach its maximum height, it will take another 8 seconds to return to its original elevation. Presuming it is lauched from flat ground and returns to the ground, its total time in flight would be 16 seconds. If it is launched from a hill, or at a hill, more information would be needed.


How can you used trigonometry in projectile motions?

when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,


Will a ball thrown almost horizontally go the furthest?

No, this is an example of projectile motion. You should throw it at 45 degrees from the horizontal ground for it to have the maximum horizontal distance. This is because a sufficient height must be achieved, so that the ball can stay in the air longer and thus travel a longer distance while in flight.


What is the value of the vertical speed at the highest point of the projectile's trajectory?

The value of the vertical speed at the highest point of the projectile's trajectory is the lowest speed at the maximum height reached.


As a projectile shot at an upward angle rises and falls what happens to its horizontal component of its velocity if you neglect air resistance?

If there wouldn't be air resistance and gravity is the only thing that is effecting the projectile, the projectile will start to fall but it horizontal velocity will remain the same. So it would slow down, it would only change height.


What is a horizontal projectile?

horizontal projectile means to project horizontaly from any height h and it forms equation of parabola if we throw any object it goes horizontal and after this it goes down and by the equation s=ut+1/2at*twe can find following things from it # time ofprojectile # distance travelled #effect of gravity


Explain the effect of changing the angle of projection on the magnitude of maximum height?

"the higher the altitude the lower the range "


What are the two types of motion a projectile has?

If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.