Acceleration cannot be measured in metres per second. There is, therefore a fundamental problem with the question.
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
2 meters every second. bit pointless
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
The average speed = 1/2 (initial speed + final speed) = 1/2 (15 + 25) = 1/2 (40) = 20 meters per second.The distance traveled = (average speed) x (time) = (20 x 7) = 140 meters.
5.0 meters every second.
At the end of 7.508 seconds, the car has traveled 62 meters, and it's speed is 16.517 meters per second.
2 meters every second. bit pointless
1249 + 2987 + 66245 = 70481
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
60.912 meters in that time
The average speed = 1/2 (initial speed + final speed) = 1/2 (15 + 25) = 1/2 (40) = 20 meters per second.The distance traveled = (average speed) x (time) = (20 x 7) = 140 meters.
gravity
5.0 meters every second.
That's easy, if the car is initially traveling at 25 meters per second and gradually accelerates 3 meters per second for 6 seconds then the car is traveling at 43 meters per second.
23.6 meters per second.
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
.052 meters per second or .09 per meter