P=2(w)+2(l)
52=2(12)+2(l)
52=24+2l
52-24=2l
28=2l
14=l
The length is 14 cm.
12 is.
432
12 meters
It could be rectangle that has a length of 6 units and a width of 2 units.
Perimeter= 2length x 2widthSince the perimeter is 40 and 2 times the width is 16, that means 2 times the length is 24. The length is 12.
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
The perimeter is found by multiplying the width by the length. So divide 50 by 12 and you get 4.166 width.
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
width=5 length=12
Perimeter = 12+12+3+3 = 30m
12 is.
432
Perimeter = 12+12+3+3 = 30 m
12 meters
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
It could be rectangle that has a length of 6 units and a width of 2 units.