L + W = P/2 = 20; L = 5W so 6W = 20 so width is 3 and one third cm, length is 16 and two thirds cm
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
That would be 3 x 9 inches.
length times width
4cm by 13cm
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
That would be 3 x 9 inches.
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
length times width
Length + width = half the perimeter, but more info eg area, is needed.
4cm by 13cm
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
The dimensions of the rectangle are 21 units by 9 units
22+27+22+27
64 meters
There is no reason for the perimeter of a triangle to have any relation to the perimeter of an unrelated rectangle!