L + W = P/2 = 20; L = 5W so 6W = 20 so width is 3 and one third cm, length is 16 and two thirds cm
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
That would be 3 x 9 inches.
length times width
4cm by 13cm
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
That would be 3 x 9 inches.
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
To find the dimensions of the rectangle, we need to set up equations based on the given area and perimeter. The area of a rectangle is length multiplied by width, so length times width equals 12 cm. The perimeter of a rectangle is given by the formula 2(length + width), which in this case equals 16 cm. By solving these two equations simultaneously, we can find the dimensions of the rectangle.
length times width
Length + width = half the perimeter, but more info eg area, is needed.
Ah, what a lovely question! To find the perimeter of a rectangle, we need to know both the length and width. Since the area is 432 square feet, we can find the dimensions by factoring 432 into pairs of numbers until we find a pair that could be the length and width of the rectangle. Once we have the dimensions, we can simply add up all the sides to find the perimeter.
4cm by 13cm
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
The dimensions of the rectangle are 21 units by 9 units
22+27+22+27
There is no reason for the perimeter of a triangle to have any relation to the perimeter of an unrelated rectangle!