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A rectangular picture frame is 3 inches wider than it is taller The total length of the four sides is 38 inches How do you find the measurement for each of the sides?
Well, let's see . . .
-- Let's call the height (tallness) ' T '.
-- You said the width is 3 inches more than the tallness, so the width is (T + 3).
-- The frame is a rectangle. So, if an ant wants to walk around the whole frame,
he would have to walk along the width twice and along the height twice. His
route would have four straight parts, and the whole route would be
( T ) + (T + 3) + ( T ) + (T + 3) .
If the ant added all of those up, he would have (4T + 6). So would you.
Now, you also said that the total length of the four sides is 38 inches. OK, so
4T + 6 = 38
Subtract 6 from each side of this equation:
4T = 32
Divide each side by 4 :
T = 8
Great !
' T ' is the height of the frame. That's 8 inches.
The width is 3 inches more. That's 11 inches.
The total length is (2 widths) + (2 heights) = (2 x 11) + (2 x 8) = 22 + 16 = 38 inches. yay!
What else can I help you with?
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Possibly, but not necessarily. It could be length and height. Or, it could be in the context of a shape which is not even rectangular.
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The width of a rectangle is the shorter measurement and length is the longer. So in the case of the picture frame, 6 inches would be the width, and 10 inches would be the length.
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