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What is the sum of the measures of the interior angles of the regular polygon if each exterior measures 120?
Hint: in a regular polygon interior plus exterior = 180o, always.
What polygon that measures one interior angles of 162 degrees?
It is a regular 20 sided polygon
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What is the sum of the interior angles of a regular polygon if each angle measures 20 degrees?
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
What is the sum of the measures of the interior angles of a regular polygon if the exterior angles are 72?
Each interior angle measures 108 degrees and the 5 angles of the regular pentagon add up to 540 degrees
What measure of the interior angles of a polygon is 720 degrees?
If it's a regular polygon then each interior angle measures 120 degrees.
What is the number of sides of a regular polygon if one interior angle measures 90?
A four-sided regular polygon (square or rectangle) has 900 interior angles.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
What is the sum of the measures of the interior angles of a regular polygon if each angle measures 120 degrees?
cheat!
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
The sum of the measures of the interior angles of a regular polygon is 1800 what is the measure of each interior angle?
The polygon will have 12 equal sides and each interior angle measures 150 degrees.
