Best Answer

Length = 38 feet

Width = 19 feet

Check: 2*(38+19) = 114 feet

Q: A room has a perimeter of 114 feet if it is twice as long as it is wide what are its dimensions?

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Length of the table is 10 feet.

15m wide and 31m long

The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36

It is a rectangle and its perimeter is 12+12+6+6 = 36 feet

12

Related questions

If the given dimensions are that of a rectangle then perimeter is: 34 feet

Well, if you're talking about a square, then the perimeter is twice the length plus twice the width; in this case it would be 30 feet...

Length of the table is 10 feet.

The dimensions are length 50 yards and width 25 yards

A square with an area of two acres is 295.2 feet long on each side, with a perimeter of 1,181 feet.

15m wide and 31m long

The area is 72 The dimensions would be 6x12 6 * 2 + 12 * 2 = 36

An acre contains 43,560 square feet. So half that would be 21,780 square feet. The dimensions can vary as long as it gets to that size. An approximation would be 105 feet by 207 feet.

Assuming the table's surface is a rectangle, the width is 4 feet. The length is 8 feet. The perimeter is therefore (4 + 8) x 2 = 24 feet.

The perimeter doesn't tell you the dimensions. It doesn't even tell you the shape.

Each of the short sides is 7 feet long and each of the long sides is 7x2 (14) + 3 which equals 17 feet long. So the width is 7 feet.

80 feet