Assuming the table's surface is a rectangle, the width is 4 feet. The length is 8 feet. The perimeter is therefore (4 + 8) x 2 = 24 feet.
48ft
8
This depends on where the table is located.If it is a direct child of the body-element, the table width will be a percentage of the browser window width.Otherwise the width will be the percentage of the parent element's width.Therfore, if a table of width 50% is inside a div of width 600px, the table's width will actually be 300px.
You tell the table to use 100% of the available width. Here is an example: <table width="100%>. The width of each cell is an equal proportion of the table width.
Yes, it's possible to align tables next to each other using the float value of the style attribute. Give both tables the same float and a fixed width and they will appear next to each other if the browser window is wide enough. Example: <table style="float:left; width:100px;"> <tr><th>Table 1</th></tr> <tr><td>Content</td></tr> </table> <table style="float:left; width:100px;"> <tr><th>Table 2</th></tr> <tr><td>Content</td></tr> </table> This will create two tables of the width 100px next to each other.
It can be done, by using a rowspan=2 and colspan=2 in the first cell on the first row. <Table Border=1 width=150 height=150> <TR><TD Rowspan=2 colspan=2>A</TD><TD>B</TD></tr> <TR><TD>C</TD></TR> <TR><TD width=50>D</TD><TD width=50>E</TD><TD width=50>F</TD></TR> </TABLE>
By default, the cell widths of an HTML table are generally proportional based on their contents. In MS Office applications, they are typically equalby default.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
Length = (Perimeter - twice width) / 2
Twice the (width plus length)
Subtract twice the width from the perimeter. The answer will be twice the length. Divide by two.
12 meters
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
It is 2*(Length + Width).
The perimeter of a rectangle is twice the width added to twice the length -> 2(W) + 2(L) We are told that for this rectangle the perimeter = 2(W) + 110 So for this rectangle 2(L) = 110 Therefore L = 55 But this does not tell us enough to work out the width ..... if the width is 1 cm then the perimeter would be 2(1) + 110 and if the width is 300 cm then the perimeter would be 2(300) + 110 In each case the perimeter meets the requirement of being 110 cm more than twice the width.