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A stone is thrown horizontally at 8 ms from a cliff 78.4 m high how far from the base of the cliff will the stone strike the ground?
According to the Laws of Physics, Horizontal Velocity is unaffected by Vertical Velocity. Thus you need to first find how long it will take the stone to hit the ground.
Assume:
Acceleration due to gravity = 9.8 m/s^2
Velocity due to gravity = 9.8x m/s, where x is seconds
Displacement due to gravity = 9.8x^2 m, where x is seconds
Set Displacement = to 78.4m
78.4m = 9.8x^2 m
and solve for..
x = sqrt(8) = 2 sqrt(2)
Then to find displacement horizontally, multiply time*velocity horizontally
distance from base of cliff = (2 sqrt(2))s * 8 m/s = 16 sqrt(2) m
What else can I help you with?
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
64 METERSA+
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How fast was the ball thrown?
10 m/s
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How high was the cliff rounded to the nearest meter?
Answer: 44 meters
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
64 METERSA+
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How fast was the ball thrown?
10 m/s
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How high was the cliff rounded to the nearest meter?
Answer: 44 meters
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff How long was the ball in the air?
Answer: 3 seconds
What object exhibit two dimensional?
An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall
A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
"3.2" or "3.20" please put all of that
A ball is thrown horizontally at 20 from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high. How far from the base of the cliff does the ball strike the ground?
the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters
A ball thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?
If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.
A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff. How long was the ball in the air3?
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
