If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt)
It also took 4 secs to travel vertically.
It started with a vertical velocity of 0 m/s.
Using x=v0 + (1/2) a t2
a = -g ( Acceleration due to gravity 9.8m/s2)
x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m
It fell 78.4 meters before coming to a stop.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
10 m/s
64 METERSA+
Answer: 44 meters
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
10 m/s
Answer: 3 seconds
64 METERSA+
Answer: 44 meters
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
"3.2" or "3.20" please put all of that
22.35294117647059
It doesn't matter whether the object is thrown down, up, horizontally, or diagonally. Once it leaves the thrower's hand, it is accelerated downward by an amount equal to acceleration of gravity on the planet where this is all happening. On Earth, if you throw an object horizontally, it accelerates downward at the rate of 9.8 meters per second2 ... just as it would if you simply dropped it. Whether it's dropped or thrown horizontally, it hits the ground at the same time.
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.