108, 126, 144, 162, 180, 198, 216, 234, 252, 270, 288 and 306, to name a few.
The least three-digit number that is divisible by both 5 and 9 is 135.
A three-digit number divisible by both 2 and 5 must end with a 0, as this is the only digit that satisfies both conditions. The smallest three-digit number is 100, and the largest is 999. Therefore, any three-digit number that ends in 0, such as 100, 110, or 990, is divisible by both 2 and 5.
2
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
26.
240
990.
102
888
40*36 = 1440 is divisible (not divisable) by both. It is not the samllest such number, but that was not required by the question.
There are only two smaller 3-digit numbers and both of them have repeated digits.
The one digit number that has the same number of factors as the number six is three. Six's factors are 1, 2, 3, and 6 while three's factors are 1 and 3. Therefore, both numbers have the same number of factors.