108, 126, 144, 162, 180, 198, 216, 234, 252, 270, 288 and 306, to name a few.
A three-digit number that is divisible by both 3 and 4 must also be divisible by 12, since 12 is the least common multiple of 3 and 4. The smallest three-digit number is 100, and the largest is 999. The first three-digit number divisible by 12 is 108, and an example of a three-digit number meeting this criterion is 120.
The least three-digit number that is divisible by both 5 and 9 is 135.
A three-digit number divisible by both 2 and 5 must end with a 0, as this is the only digit that satisfies both conditions. The smallest three-digit number is 100, and the largest is 999. Therefore, any three-digit number that ends in 0, such as 100, 110, or 990, is divisible by both 2 and 5.
2
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
26.
240
990.
102
888
40*36 = 1440 is divisible (not divisable) by both. It is not the samllest such number, but that was not required by the question.
There are only two smaller 3-digit numbers and both of them have repeated digits.