pH = -log10(Ka) - log10([HA]/[A-]) = 3.41 -log10(1.35) = 3.41 - 0.1313 = 3.28
A line of reasoning showing more steps is: By definition, Ka = [H+][A-]/[HA], where the brackets indicate molar concentrations. Dividing both sides of this equation by [A-]/[HA] and substituting the numerical values given results in [H+] = (10.92 X 10-3)(3.887 X 10-4)/(8.07 X 10-3) = 5.260 X 10-4. The log of 5.260 =0.7210, so the pH of this solution is - (-4 - 0.7210) = 3.28, to the justified number of significant digits (limited by 8.07).
It would be named as a dilute solution of a weak acid.
no it doesn't.dissolving or making a solution of an acid makes a more dilute solution of the acid.
There are 48 mL of acid in 320 mL of a 15% acid solution. This is calculated by multiplying the volume of the solution by the percentage of acid in the solution: 320 mL x 0.15 = 48 mL.
One gallon of muriatic acid weighs approximately 9 pounds, and it typically contains about 31-38% hydrochloric acid. To calculate the weight of dry acid in one gallon of muriatic acid, you would need to consider the concentration of hydrochloric acid in the solution.
To find the amount of pure acid to add, set up an equation based on the amount of acid in the original solution and the final solution. Let x be the amount of pure acid to add. The amount of acid in the original solution is 0.4 × 12 = 4.8 ounces. The amount of acid in the final solution is 0.6 × (12 + x) = 4.8 + 0.6x ounces. Therefore, to get a 60% acid solution, you would need to add 10.67 ounces of pure acid.
The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol
pH of the strong acid solution will be lower than the pH of the weak acid solution due to the stronger dissociation of the strong acid.
Ammonia reacts with an acid to form ammonium ions and water. The reaction between ammonia and an acid is typically used in chemical processes to neutralize the acidity of the solution.
At a pH of 7, both statements are true. The hydroxide ion concentration equals the hydronium ion concentration in a neutral solution with pH 7. Additionally, in a neutral solution, the concentration of the acid equals the concentration of the conjugate base since the solution has an equal balance of H+ and OH- ions.
The name of HF in solution is hydrofluoric acid.
The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.
It would be named as a dilute solution of a weak acid.
Nitrous acid in solution can be written as HNO2(aq).
The presence of an acid lowers the pH of the solution in water.
To create a 400 L solution that is 62% acid, you would need 200 L of the 80% acid solution and 200 L of the 30% acid solution. This would result in a final solution with the desired concentration.
no it doesn't.dissolving or making a solution of an acid makes a more dilute solution of the acid.
A weak acid refers to the extent to which the acid dissociates in a solution, while a dilute acid refers to the concentration of the acid in a solution. Therefore, they are not the same but can be related in the sense that a weak acid may be present in a dilute solution.