6 ounces
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
how many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
The final percent concentration of the solution would be approximately 12.0% methanol. This is calculated by dividing the volume of methanol by the total volume of the solution (600 ml / 5000 ml) and then multiplying by 100 to get the percentage.
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
Acetic acid is added to the solution, but the pH of the solution does not change. Sodium hydroxide, a base, is added to the solution, but the pH of the solution does not change.
add 25ml more of solution x * 20 = 100 * 25 x = 25
NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20
2%
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
10 liters.
add 4 parts water per part solution
The original mixture contains 41.4 ounces of glycol. for this to be 30 percent of the mixture, the total mixture must be 138 ounces, so 46 ounces of water must be added.
20%
4 litres
50 gallons @ 3% must be added.
98 mL