When i will be a pro will help
Not really. Neglecting air resistance just makes it easier to solve equations and grasp concepts. If one were to actually be collecting data from your experiment, they would have to take in air resistance, especially if the object's cross section were high and/or density was low.
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
There are several different "oval" shapes. A running track, which comprises two semicircles separated by two straight stretches is an oval. So is the cross section of an egg - a shape in which the cross-sectional width does not change uniformly. Another example is the ellipse. Because all these shapes are called ovals, there is no single name.
The answer depends on what the section is of.
1 section = 640 acres. A quarter section = 160 acres.
A piece of wire stretched such that its length increases and its radius decreases will tend to have its resistance increase. The formula for this is: R = ρL/A where ρ = resistivity of the material composing the wire, L = length of the wire, and A = area of the conducting cross section of the wire. It can easily be seen that as area decreases resistance gets higher. In the case proposed the wire length is not reduced as it is stretched to reduce the area, this increases the resistivity as well.
Yes. The bigger the cross section, the lower the resistance.
If two pieces of wire are made of the same material and have the same length but different resistance, then the one with the greater cross section area has the lower resistance.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
No. Resistance does.
Assuming constant cross section, the resistance is directly proportional to the length.
Resistance is inversely proportional to cross-sectional area. so ,if the thickness of the wire increases, the area of cross-section increases and this results in decrease of the resistance. The resistance R = l p / A where R is the resistance, l is the length of the wire, p(rho) is the electrical resistivity of the material and A is the area of cross section. So R the resistance is inversely proportional to A the area of cross-section. If R increases
The amount of air resistance an object has depends on it's shape and it's frontal cross-section.