There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
50%
Recessive allele is a trait that doesn't show in one's phenotype (observable trait) if there is a dominant allelle present. Only when you inherit a recessive allele from both parents (aa for example and not Aa) does the trait show in your phenotype.
chromosome segregationIf the character is governed by a single allele and it is dominant, than its probability to be in the gamete is 75%.
"h@vOk"
Yes
Color Blindness is x-linked recessive. Therefore, it could not be heterozygous; the daughter would not be colorblind, but rather have normal vision.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
Being Colorblind means you recieved 2 recessive alleles from you parents. So that means the mother and father must of had 2 recessive alleles. Also Colorblindness is more common in males.
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
50%
It is called x-linked alleles. It is rare for a female to have color blindness because the allele must be passed from both parents. Males only need one allele to be color blind.With the equation, color blind female and non-color blind male reproduce. Each son has a 50% chance of developing the disorder.
carried on the x chromosome
She has at least one recessive color blindness allele {apex}
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
Each parent must have the recessive allele for colorblindness.
True
It is sex-linked