That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
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Bho
Find the coordinates of the vertices of triangle a'b'c' after triangle ABC is dilated using the given scale factor then graph triangle ABC and its dilation A (1,1) B(1,3) C(3,1) scale factor 3
The answer will depend on the original coordinates of A: these have not been provided so neither has an answer.
That would depend on its original coordinates and in which direction clockwise or anti clockwise of which information has not been given.
The coordinates of the point P would be definitely 3 6.
(eg. Aa Bb Cc) First would be to find out all the different combinations of these traits ABC ABc AbC Abc aBC aBc abC abc Then would be to make a "cross" out of them ABC ABc AbC Abc aBC aBc abC abc ABC ABc AbC Abc aBC aBc abC abc Then would be to 'fill in' the cross by adding them up ABC ABc AbC Abc aBC aBc abC abc ABC AABBCC AABBCc AABbCC AABbCc AaBBCC AaBBCc AaBbCC.... ABc AbC Abc aBC aBc abC abc Hope the rest you can figure out, Sincerely, *diag*
this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D
yes abc=abc
The area is calculated easily using the determinant of the matrix of coordinates, or Heron's formula and is 15 square units.
Because a,b, and c are the first three letters of the alphabet