In general it is not possible.
Modern data encryption depends on the fact that there are numbers that are products of two very large primes: primes so large that even very powerful computers are not be able to factorise the numbers in a sensible amount of time.
All the smallest factors of a number must be its smallest factor, which for any number is 1, so: loop loop loop print "Enter an integer number: ": input n until num(n) do print "Please enter a number" repeat until n = int(n) do print "Please enter an integer" repeat print "Smallest factor of ":n:" is 1" repeat
# Ruby code print 'Enter n: '; n = gets.to_i n.times { | i | puts ( i + 1 ) ** 2 if ( i + 1 ) % 3.0 == 0.0 }
Once all the prime factors of a number have been found, the number of factors the number has and what they are can be found. I'd be finding the prime factors first before finding all the factors of a number, so I'd rather find all the prime factors as it means I can stop before I have to do more work in finding all the factors.
"Proper factors" are all of a number's factors except one and the number itself.
All the factors of the number 11 are: 1 and 11. This is because 11 is a prime number.
All factors except the number itself or unity are "proper factors", the excluded ones being tautological.
No.
CLS PRINT "PROGRAM: Print squares of all even numbers from 1 to 20" PRINT PRINT "number", "squared" PRINT FOR number% = 1 TO 20 IF number% MOD 2 = 0 THEN PRINT number%, number% * number% END IF NEXT END
That's an infinite list; too long to print here.
There are a few factors for the number 1,260. The factors for this number are 1,2,4,5,10,13,20,26,52,65,130 and 260.
How to know that you found all the factors for example my teacher taught me that when u reach a double diget number that is all the factors. ( 6x6)-~ double diget number
Hi