4f + 5
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
C# 5 times, then D# 5 times, then G# 4 times, and then, depending on which part of the song, it's F on the D string 5 times or F on the C string 5 times. Happy Viva la Viding!! ;-)
4/5 (4 + f) = 4(4+f)/5
5 times the function of f
5 +1/4 f = 5 + f/4
If you take the degrees Celsius times 9/5 and add 32 degrees, you will get the degrees Fahrenheit. °C x 9/5 + 32 = °F
C divided by 5 times 9 the add 32.-100 divided by 5 then times 9 then add 32=-148Memorize you benchmarksC F-40= -400 = 32100= 21237= 98.6
f = 202 because 7*5*202 = 7070
f(x) = (3x - 4)/5 f(0) = [3(0) - 4]/5 = -4/5
It's not solvable: Proof that it's not solvable: 2 simultaneous equations - let F =father and S=son F = 4S (father is 4 times son's age) and F-5=7S (father minus 5 years equals 7 times son's age). Combining both gives 4S=7S+5 which is 3S=-5. Clearly you cannot have a negative age, which makes the question nonsensical.
^ means "to the power of" F ^ 2 + 4 = 5 ^ 2 F ^2 +4 = 25 F ^2+4 -4 = 25 -4 F^2 = 21 F = (square root of 21)
Let F = Fahrenheit Let C = Celcius Let K = Kelvin F = 9/5 C +32 C = K -273 F = 9/5 (K-273) +32 F = 9/5K - 491.4 +32 SINCE F = K then F = 9/5 F - 491.4 +32 459.4 = 9/5 F - F 459.4 = 9/5 F - 5/5F = 4/5 F 459.4 = 4/5 F F = 5/4 (459.4) = 574.2