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The sum of the 10th, 11th and 12th terms = 129 therefore the value of the 11th term is 129/3 = 43.

The sum of the 19th, 20th and 21st terms = 237 therefore the value of the 20th term

is 237/3 = 79.

The difference between the 20th and 11th terms is 79-43 = 36 therefore the common difference is 36/9 = 4.

Using the 11th term gives us 43 = 11 x 4 + a, therefore a = -1.

The AP is therefore -1 + 4n

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Q: An AP consists of 21 termsThe sum of the three terms in the middle is 129 and of the last three is 237Find the AP?
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