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The runway must be long enough for the aircraft to reach take-off velocity and then stop. We have to find out how much distance it takes the aircraft to reach 100 m/s and then stop. For this we can use the equation v2 = v02 + 2ax.

To reach 100 m/s: 1002 = 2(11)x. Solving for x gives x = 454.5 so it takes 454.5 meters for the aircraft to reach 100m/s.

To slow back down: 02 = 1002 + (2)(-9)x. Solving for x gives x = 555.5, so it takes the aircraft 555.5 m to stop.

The total distance of the runway needs to be 454.5 + 555.5 = 1,010 m.

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