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The formula for distance covered during uniform acceleration is

d = 1/2 * (vf + vi) * t (1)

Time, t, is given; initial velocity, vi, is 0; but final velocity, vf, is unknown and must be computed from given information. Knowing the rate of acceleration, initial velocity and time, The final velocity may be computed using the formula for average acceleration (actual acceleration under uniform motion) which is

a = (vf - vi) / t (2)

Rewriting to solve for vf with vi = 0 we have

vf = a * t

vf = 6m/s2 * 12s

vf = 72m/s

Plugging this value into equation (1) with the other given values we have

d = 1/2 * (72m/s + 0 m/s) * 12s

d = 432m

So the airplane will travel 432m from rest in 12 seconds under 6m/s uniform acceleration.

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Q: An airplane originally at rest on a runway accelerates uniformly at 6 meters per second for 12 seconds During this 12-second interval the airplane travels a distance of approximately?
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