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An electric lamp is marked 100w and 220v it is used for 5 hours daily calculate its resistance while glowing and energy consumed in kw per day?
Wiki User
∙ 13y ago
power = voltage x current; current = power / voltage = 25W / 220V = 0.11...A
resistance = voltage / current = 220V / 0.11A = 1936 ohms
power = energy / time; energy = power x time = 25W x 1 day = 0.025kW x 1 day = 0.025 kW-days or 0.6 kW h
note: energy is not measured in kw per day, usually kW-hours (kW h).
Wiki User
∙ 13y ago
Wiki User
∙ 13y agoIf the lamp consumes energy at the rate of 100w when energized by 220v, then its resistance is
E2/P = (220)2/100 = 484 ohms.
"Kw" is not a unit of energy. Some units of energy are:
-- kilowatt-hour
-- watt-hour
-- watt-second (joule)
-- newton-meter (joule)
-- foot-pound
(100 watts) x (5 hours per day) = 500 watt-hours per day = 1/2 Kilowatt-hour per day.
(500 watt-hour/day) x (3,600 sec/hour) = 1,800,000 joules (1.8 megajoules) per day
Wiki User
∙ 13y agoTo calculate the resistance, you might first calculate the current: 25 W / 220 V = 0.114 A. Resistance: R = V / I = 1930 Ohms.
Energy is 25 W = 25 watt-second per second. Multiply that by 86400 (seconds per day), and you get 2160000 ws/day. Divide that by 3.6 million, to get 0.6 kWh per day.
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