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The equation for magnetic force is:

F = q(v × B)

Thus;

F = (1.60 × 10 -19C)(3 × 106 m/s)(2 T) = 9.6 × 10-13 N

F = ma

a = F/m = (9.6 × 10-13 N)/(9.11 × 10-31 kg) = 1.05 × 1018 m/s2

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Q: An electron has a velocity of 3 x 10 to the 6th power meters per second perpendicular to a magnetic field of 2T what force and acceleration does the electron experience?
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