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5.10 x 10^14 hz

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11y ago
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11y ago

588 nm

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13y ago

Long way. Energy = Planck's constant * speed of light/lambda in meters

3.8 X 10^-19 J = (6.626 X 10^-34 J*s)(2.998 X 10^8 m/s)/ Lambda in meters

= 5.2 X 10^-7 meters, which is ~ 523 nanometers in wavelength.

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13y ago

Energy = Planck's constant * speed of light/Lambda(wavelength)

4 X 10^-17 J = (6.626 X 10^-34J*s)(2.998 X 10^8m/s)/Lambda

= 4.97 X 10^-9 meters or, 4.97 nanometers ( short wavelength )

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14y ago

E=hC/λ rearranges to λ=hC/E

λ= (6.63 x 10-34) x (3 x 108) / 3.8 x 10-19

λ= 5.23 x 10-7m

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8y ago

The wavelength is 609,34 nm.

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14y ago

522 nm

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12y ago

588 nm

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Q: An electron requires 3.8 x 10-19 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?
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An electron requires 4.4 x 10-19 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?

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An electron requires 4 x 10-17 J of energy to be removed from its atom What is the wavelength of a photon that has this much energy?

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