5.10 x 10^14 hz
588 nm
Long way. Energy = Planck's constant * speed of light/lambda in meters
3.8 X 10^-19 J = (6.626 X 10^-34 J*s)(2.998 X 10^8 m/s)/ Lambda in meters
= 5.2 X 10^-7 meters, which is ~ 523 nanometers in wavelength.
Energy = Planck's constant * speed of light/Lambda(wavelength)
4 X 10^-17 J = (6.626 X 10^-34J*s)(2.998 X 10^8m/s)/Lambda
= 4.97 X 10^-9 meters or, 4.97 nanometers ( short wavelength )
E=hC/λ rearranges to λ=hC/E
λ= (6.63 x 10-34) x (3 x 108) / 3.8 x 10-19
λ= 5.23 x 10-7m
The wavelength is 609,34 nm.
522 nm
588 nm
440 - 460 nm
Drops to a lower energy level and emits one photon of light.
Radio waves are longer than X-rays and because energy is inversely proportional to wavelength, X-Rays have more energy. The formula is 1.25uevm/wavelength, that is the energy is 1.25 micro electron volt divided by the wavelength in meters.
The smallest drop of an electron between two energy states in an atom flips out a photon of radio with a frequency of about 1,420 MHz (wavelength = about 21 centimeters).
It is possible if the electron absorbs energy, for example, from a photon.
450 nm
4.8 - 5.2 nm
440 - 460 nm
The wavelength is w = hc/E = .2E-24/4E-17 = 5E-9 meters.
The energy to remove 1 electron is the first ionization energy. To remove a second electron requires more energy. This is because the electron being removed now has to overcome the +1 positive charge introduced after the 1st electron was removed.
The shorter the wave length the more energy. The further the electron falls, the more energy that will be emitted and the shorter the wavelength.
an electron
The 3s.
electron lost 3.6 x 10-19 -barbie=]
Shorter wavelength = more energy. The farther the electron falls, the more energy that will be emitted.
Type your answer here... when adding an electrons to oxygen it needs more energy in electron affinity in order to attract electrons from other atoms to be stable.and we know that oxygen is in short of two electrons.so in the other hand when an electron is removed from oxygen it will be unstable and will be needing more ionization energy to be able to remove an electron to it.Thus mean indeed when adding or removing electrons for oxygen it requires energy.
Ionization energy represents the energy required to remove electrons from an atom. The first and second ionization energies are relatively small because the lectrons must be removed from the 2s orbital. For the third ionization energy the electron must be removed from the 1s orbital which has less energy than the 2s, and so requires much more energy to be removed.