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An object is undergoing simple harmonic motion with period 1.210 s and amplitude 0.610 m. At t equals 0 the object is at x equals 0. How far is the object from the equilibrium position at time 0.485 s?
Wiki User
∙ 14y ago
I got -0.495 m. I can't promise you this is correct, but here's my method:
the position as a function of time is x(t)=A*cos(sqrt(k/m)*t)
you already have A and t values, and you can solve for sqrt(k/m) by using the period they gave you.....
T=2pi/(sqrt(k/m))
sqrt(k/m)=2pi/T
Plug and chug. Bada bing.
Wiki User
∙ 14y ago
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