use the formula W = mgs
W stands for work done in joules
m stands for mass of the object
g stands for gravity
s stands for the distance the object is lifted
W = mgs
W = 78kilograms•9.8m/s2•6meters
W = 4586.4 J (joules) answer would be 4,586.4 J
An object with a mass of 78 kilograms is lifted through a height of 6 meters. How much work is done?
it is impossible to know you have to give a velocity to get its momentum otherwise you cannot determine this answer.
the answer is -D. 1,440.6 (I just took the test) :)
C. 1,440.6 j
question 24 on penn foster is C.
Work = (force) x (distance) = 7 x 2.4 = 16.8 joules
I believe that when you say 'lifted through', you mean lifted to a height of 10m. If so, the amount of work is such: Work= Force x Distance which have the units (Joules = Newtons x meters) When the object is lifted, it increases in its potential energy. The equation for this is: Potential energy = mass x gravitational force x height = 4.5 x 9.81 x 10 =441.45 Joules As 1 joule = 1 newton x meters and we have 441.45 Joules, 441.45 joules of works is done! :D
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
700 x 4 = 2,800 newton-meters = 2,800 joules
The idea here is to multiply the force by the distance.
a fallen treee is lifted 2.75 meters. How much work is done?
Work = Force x distance = 700N x 4m = 2800N•m = 2800 Joules
Work = force x distance = 20 x 2 = 40 newton-meters = 40 joules
Work is force x distance = 700 x 4 = 2800 Joules
Work = Force (N) x Distance (m) Therefore, the units of work are N-m, or Newton-meters. F=700N D=4m W=FxD = 700x4 = 2800N-m
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.