true
NO- by definition a set is not a proper subset of itself . ( It is a subset, but not a proper one. )
Because every set is a subset of itself. A proper subset cannot, however, be a proper subset of itself.
yes, if the set being described is empty, we can talk about proper and improper subsets. there are no proper subsets of the empty set. the only subset of the empty set is the empty set itself. to be a proper subset, the subset must be strictly contained. so the empty set is an improper subset of itself, but it is a proper subset of every other set.
No, by definition. A proper subset is a subset that contains some BUT NOT ALL elements of the original set.
A subset of a set S can be S itself. A proper subset cannot.
The set {1, 3} is a proper subset of {1, 2, 3}.The set {a, b, c, d, e} is a proper subset of the set that contains all the letters in the alphabet.All subsets of a given set are proper subsets, except for the set itself. (Every set is a subset of itself, but not a proper subset.) The empty set is a proper subset of any non-empty set.This sounds like a school question. To answer it, first make up any set you like. Then, as examples of proper subsets, make sets that contain some, but not all, of the members of your original set.
No. The null set cannot have a proper subset. For any other set, the null set will be a proper subset. There will also be other proper subsets.
I believe the term "proper set" is not use in math. A "proper subset" is a subset of a given set, that is not equal to the set itself.
A set "A" is said to be a subset of of set "B", if every element in set "A" is also an element of set "B". If "A" is a subset of "B" and the sets are not equal, "A" is said to be a proper subset of "B". For example: the set of natural numbers is a subset of itself. The set of square numbers is a subset (and also a proper subset) of the set of natural numbers.
NO
Let A be the set {1,2,3,4} B is {1,2} and B is a proper subset of A C is {1} and C is also a proper subset of A. B and C are proper subsets of the set A because they are strictly contained in A. necessarily excludes at least one member of A. The set A is NOT a proper subset of itself.
Assume that set A is a subset of set B. If sets A and B are equal (they contain the same elements), then A is NOT a proper subset of B, otherwise, it is.