no
If: x+16 = 9x then x = 2
x=-7
8x + 9x = x(8 + 9) = x(17) = 17x
So 17 = 9x, making x = 1 and 8/9
12x + 17 - (9x - 2)Eliminate parentheses:12x + 17 - 9x + 2Combine the 'x' terms:3x +17 + 2Combine the numerical terms:3x + 19
Presuming 1.2222222 is intended to be 1.2repeating: 1.2222222...=11/9 Presuming 1.77777 is intended to be 1.77777repeating: 1.77777...=16/9 How did we do this? Both work by the same principle, so I'll show how to solve one and you should then be able to solve the other. Let x=1.77777..., then 10x=17.7777.... . Then, 10x - x = 17.7777... - 1.77777..., continuing using algebra: 9x = 17 - 1, 9x = 16 x = 16/9. Eddie O.
If you are looking for the value of x... X=4
3x2 - 9x - 912 = 3(x2 - 3x - 304) = 3(x - 19)(x + 16).
9x is the lowest common multiple. (9x * 1 = 9x) (x * 9 = 9x)
x-17 = 16-5 x = 16-5+17 x = 28
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4
x2-9x can be factored by taking x out of each term x(x-9)