4 is an integer. 1/3 is not an integer.
Only whole numbers (1, 2, 3, -1, 500, 1,999, etc.) can be integers.
Let the first of the three odd consecutive integers be x, so that the second of these integers would be x + 2, and the third one would be x + 4. We have: 3x = 2[(x + 2)+ (x + 4)] + 3 3x = 2(2x + 6) +3 3x = 4x + 12 + 3 (subtract 4x to both sides) -x = 15 (multiply by -1 to both sides) x = -15 (the first one) So the integers are -15, -13, and -11. The average of those integers is (-15 + -13 + -11)/2 = -39/2 = -19.5.
No. you could have, for example, -4 or 4 (or any other minus or positive number). Both are integers.
No. you could have, for example, -4 or 4 (or any other minus or positive number). Both are integers.
No.
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
No. you could have, for example, -4 or 4 (or any other minus or positive number). Both are integers.
No. you could have, for example, -4 or 4 (or any other minus or positive number). Both are integers.
Start from the last integer. Subtract 2 from it, to get the second-last. Subtract 2 from that one, to get the third-last, etc.
Sure! Five examples of integers are -3, -1, 0, 4, and 7. Integers include both positive and negative whole numbers, as well as zero.
One third of 12 is 4.
a set of integers that have a common difference of one. example: 6,7,8...or -2,-3,-4,-5...
The answer would be +9 because if both integers are positive then your answer would be + somthing so in this case 5+4 is 9 and its positive +9