5 is, 2 is not.
The factors of 215 are: 1 5 43 215
The four factors of 215 are 1, 5, 43, and 215.The factor pairs of 215 are 1 x 215 and 5 x 43.The proper factors of 215 are 1, 5, and 43 or,if the definition you are using excludes 1, they are 5 and 43.The prime factors of 215 are 5 and 43.The distinct prime factors of 215 (listing each prime factor only once) are 5 and 43.The prime factorization of 215 is 5 x 43.
2 cannot be a factor as 215 is not an even number. Factors are 5 x 43
The prime factors of 215 are: 5 and 43.
215 = 5 * 43 (So we expect 4 factors) They are as follows: 1, 5, 43, 215
factors: 1, 5, 25, 43, 215, 1075 prime factors: 5(2), 43
1, 2, 5, 10, 43, 86, 215, 430 2, 5 and 43 are prime.
Do you mean, what is it evenly divisible by? You can answer questions like these by finding the factors of the number and multiplying different factors: 215 ends in 5, so we know 5 is one if its factors. Divide by 5: we're left with 43. 43 is a prime number, it can't be factored any more. 215 is only divisible by 5 and 43. As a better example of how this technique works, consider 100. 100's factors are 5, 5, 2, and 2. By multiplying together different factors, we can discover that 100 is not only divisible directly by its factors 5 and 2, but also by 5*5, 2*2, 5*2, 5*5*2 and 2*2*5.
The factors of 430 are: 1, 2, 5, 10, 43, 86, 215, 430
1, 2, 5, 10, 43, 86, 215, 430 2, 5 and 43 are prime.
The factors of 215 are 1, 5, 43, 215 For them to be common they need to be compared to another set of factors.
1, 2, 5, 10, 43, 86, 215, 430