Q: Are all numbers that are divisible by 9 divisible by 3?

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All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.

The numbers 2, 3, and 9 are all divisible by 1.

A number is divisible by 9 if all the digits add up to 9 or are a factor of. IF the digits add up to 9 (or a factor of 9), they will automatically be a factor of 3.Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.

1350 is divisible by all of the numbers of 3, 6 and 9

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

yes because 3 fits in 9 perfectly

No. It is the other way round.

yEAH, i THINK SO

All numbers divisible by 90 are also divisible by 9 and 10

Any that are divisible by 9 are also divisible by 3.

Yes because if you add all the numbers in 2232 you get 9 witch is divisible by 3

Nine is divisible by 1, 3 and 9.

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.

They are infinite.

All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.

If the number is divisible by 3 then its divisible by 9. If you forgot what the divisble rule for three this is how, add up all the numbers then whatever the sum is and if the sum can go into three then its divisible by 3 and 9.

If you add all the digits up in one number, then divide it by 3 and it comes out even, that number is divisible by 3. Example: 32,112 3 + 2 + 1 + 1 + 2 = 9 9/3 = 3 So 9 is divisible by 3 and that is how you know if a certain number is divisible by 3. To list all the numbers divisible by three would be impossible. 3, 6, 9 and just keep adding three until you get to infinity.

For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.

If the sum of its' digits are divisible by 3 for all numbers greater than 9.

yes it is divisible by all of those numbers

It is divisible by all of those numbers.

No. For example, 9 wouldn't be prime because it is divisible by 3.

no, 18 is divisible by 9 but not by 4.

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