No. They have many multiples in common, but not all. For example, 52 is a multiple of 4, but not a multiple of 8.
All multiples MUST be multiples of 4.
the common multiples are most all of the multiples of 8
Since 8 is a multiple of 2 and 4, all multiples of 8 are also multiples of both of them. Thus, Jose and maria are both correct.
Both of them.
All multiples of 4; 4, 8, 12 and so on.
all numbers that are multiples of 4 have 2 as factor
Because 8 itself is divisible by 4
All multiples of 4 are also multiples of 2. e.g. 15 x 4 = 60. (60 is a multiple of 2 and 4) All multiples of 4 are even numbers. e.g. 4, 8, 12, 16, 18, 20, 24, 28 etc (these numbers all end in either 0,2,4,6, or 8.
Not always as for example 36 is a multiple of 4 but not of 8
All multiples of 8 are also multiples of 2, but not all multiples of 2 are multiples of 8.
All the multiples of 8 including itself
Well, honey, the common multiples of 4, 8, and 16 are numbers that all three can divide evenly into. So, the first few common multiples would be 16, 32, 48, and so on. Just keep adding 16 to get more of those bad boys. Happy counting!