No because technically its different .
They really are not
Prime numbers have two factors. The sum of their proper divisors is always 1.
Prime numbers are numbers that can only be multiplied by 1 and itself (whole numbers only) to give the same result 49 (7x7) and 81 (9x9) are not a prime number (perfect squares actually) 111 and 97 are a prime number (find me two numbers that gives the same product without using the number 1)
Perfect numbers have the form 2n-1(2n-1) where 2n-1 is a Mersenne prime. When a new Mersenne prime is discovered, so is a new perfect number.
No, all prime numbers are deficient.
No. Prime numbers are a subset of whole numbers.
Any number squared except 0 is a perfect square so it follows that prime numbers are less common than perfect squares.
Yes, numbers can have common prime factors.
Just 1.
Prime numbers or relatively prime numbers.
Perfect numbers cannot be prime numbers. Here's why:A number N is perfect if σ(N) = 2N (σ is the sum of divisors function). If there is a prime p that is a perfect number, then σ(p) = 2p. However, the only factors of p are 1 and p, so σ(p) is also equal to p+1. If 2p = p+1, then p=1, which is not prime, and 1 is defined to have only one factor, 1.
No - co-prime numbers are pairs of numbers which share no positive integer factors apart from 1. Twin prime numbers are a pair of prime numbers with a difference of 2.