6 faces and 8 vertices.6 faces and 8 vertices.6 faces and 8 vertices.6 faces and 8 vertices.
Oh, dude, it's like a math riddle! So, if a polyhedron has 10 more edges than vertices, we can use Euler's formula: Faces + Vertices - Edges = 2. Since we know the relationship between edges and vertices, we can substitute that in and solve for faces. So, it would have 22 faces. Math can be fun... sometimes.
4 faces, 4 vertices.
89 vertices and 444 faces
Vertices . . . . 8 Edges . . . . . 12 Faces . . . . . 6
Tetrahedron- (4 faces, 4 vertices) Octahedron- (8 faces, 6 vertices) Cube- (6 faces, 8 vertices)
Four faces four vertices
Nothing has 2 faces and 0 vertices.
It has 26 faces and 24 vertices
2 faces, 4 edges, and 4 vertices 2 faces, 4 edges, and 4 vertices
The number of faces is 6, the number of vertices (not vertices's) is 8.
It has 14 Faces, 24 Edges, and 12 Vertices