Area under velocity versus time graph(between two given instances of time i.e. two points on time axis) gives the displacement of the body( whose graph was plotted) between those two instances i.e. in that time interval. Area under velocity time graph can be found from definite integration if the graph is a curve.
Note: Area under velocity versus time graph gives displacement not distance covered by body.
Note: Area enclosed between the plotted curve and time axis is taken. For convenience time should be taken in the x-axis.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
Displacement is the area under the v-t graph.
The distance travelled over the time period represented by the area under the v-t graph between the end points.
the physical quantity is distance and unit is meters
change in velocity
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
Displacement is the area under the v-t graph.
its the velocity
Velocity.
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
distance travelled
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
The area of a position-time graph does not have a meaning. However, the area under a velocity-time graph is the displacement. Refer to the related link below for an illustration.
The distance travelled over the time period represented by the area under the v-t graph between the end points.
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.