Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
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Yes, a position-time graph can be created from a velocity-time graph by integrating the velocity values over time. By finding the area under the velocity-time curve, you can determine how the position of an object changes over time.
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
Motion can be represented graphically using position-time graphs, velocity-time graphs, and acceleration-time graphs. These graphs provide information about how an object's position, velocity, and acceleration change over time. Position-time graphs show the object's position at different times, velocity-time graphs show how the velocity changes over time, and acceleration-time graphs show how the acceleration changes over time.
A position-time graph shows the relationship between an object's position and time. The position of the object is typically plotted on the y-axis, while time is on the x-axis. The slope of the graph represents the object's velocity, with a steeper slope indicating a higher velocity.