2Al + 2HCl ---> AlCl3 + 5H2
To balance it, just make the different atoms on each side equal eachother. For example, there are 2 Al atoms on the left side. Therefore 2 Al atoms must be on the right side as well.
Put a 2 in front of AlCl3.
Now, you look at the Cl atoms. Because you multiplied AlCl3 by 2, you have 6 chlorine atoms (2 x 3 = 6) on the right side. So you must have 6 chlorine atoms on the left side. Multiply HCl by 6.
Now, you've balanced the Al and Cl atoms. Now all you have to do is balance the H atoms and you're done.
On the left side, you multiplied HCl by 6, so you must have 6 H atoms on the right side.
multiply H2 by 3 (3x2 = 6) to get 6 H atoms on the right side.
Now you're done. Your final balanced equation looks like this:
2Al + 6HCl ---> 2AlCl3 +3H2
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
First of all, it is "HCl" not "HCI" -- in other words the letters H-C-L, and not H-C-I. HCl is hydrochloric acid, and is made of hydrogen atom (H) and a chlorine atom (Cl). There is no such thing as HCI.2HCl means 2 of HCl. it is the coefficient. there is no such thing as prescript, only subscript. so if it were HCl2, then the Cl there would be two in count, with 1 H.
Na2SO4 + CaCl2 ----> NaCl + CaSO4 Pb(NO3)2 + KI ----> PbI2 + KNO3 NaOH + CuSO4 ----> Na2SO4 + Cu(OH)2 K2CO3 + FeSO4 ----> K2SO4 + FeCO3 CH3COONa + CuCl2 ----> (CH3COO)2Cu + NaCl HNO3 (aq) + KOH (aq) ----> H2O (I) + KNO3 (aq) Ba(OH)2(aq) + 2HCIO4(aq) ----> Ba(CIO4)2(aq) + 2H2O(I)
mg0 plus 2hci equals mgc12 plus h20
Not just unbalanced but insane. There is no compound with the formula HCI. HCl, yes but not HCI.
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
CuCl2 + H2S --> CuS + 2HCl Yes, this is the balanced equation here.
mg+2hci=mgci2 + h2
Does 2HCI plus Mg equal 2Mg atoms
CaCl2 + H2CO3 -> CaCO3 + 2HCI
Will sodium carbonate react with hydrochloric acid. 2HCI(aq) NA2CO3(aq)--- 2NaCI(aq) H2O(aq) CO2(aq)?
the short answer is Yes...2HCI + CaCO3 becomes CACL2 + H2CO3 the H2CO3 decomposes to water and CO2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2