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2Al + 2HCl ---> AlCl3 + 5H2

To balance it, just make the different atoms on each side equal eachother. For example, there are 2 Al atoms on the left side. Therefore 2 Al atoms must be on the right side as well.

Put a 2 in front of AlCl3.

Now, you look at the Cl atoms. Because you multiplied AlCl3 by 2, you have 6 chlorine atoms (2 x 3 = 6) on the right side. So you must have 6 chlorine atoms on the left side. Multiply HCl by 6.

Now, you've balanced the Al and Cl atoms. Now all you have to do is balance the H atoms and you're done.

On the left side, you multiplied HCl by 6, so you must have 6 H atoms on the right side.

multiply H2 by 3 (3x2 = 6) to get 6 H atoms on the right side.

Now you're done. Your final balanced equation looks like this:

2Al + 6HCl ---> 2AlCl3 +3H2

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15y ago

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