Calculate the mass, in grams, of each of the following samples.1.7 mol aluminum 1.400e-15 Tmol carbon dioxide 7.7e12 pmol of sodium nitrate 2.73e-4 kmol of C2H6O 1.02 ✕ 10-9 Mmol of uranium 4.01 mmol hydrobromic acid?

Answer 1

Mass (g) = Number of moles (mol) x Molar mass (g/mol)

Here are the calculations for each sample:

7 moles of aluminum (Al):

The molar mass of Al is approximately 26.98 g/mol.

Mass = 7 mol x 26.98 g/mol = 188.86 g

1.400e-15 teramoles (Tmol) of carbon dioxide (CO2):

The molar mass of CO2 is approximately 44.01 g/mol.

Mass = 1.400e-15 mol x 44.01 g/mol = 6.16e-14 g

7.7e12 picomoles (pmol) of sodium nitrate (NaNO3):

The molar mass of NaNO3 is approximately 85 g/mol.

Mass = 7.7e12 mol x 85 g/mol = 6.59e-10 g

2.73e-4 kilomoles (kmol) of C2H6O:

The molar mass of C2H6O (ethanol) is approximately 46.07 g/mol.

Mass = 2.73e-4 mol x 46.07 g/mol = 0.1256 g

1.02e-9 megamoles (Mmol) of uranium (U):

The molar mass of uranium is approximately 238.03 g/mol.

Mass = 1.02e-9 mol x 238.03 g/mol = 2.43e-7 g

4.01 millimoles (mmol) of hydrobromic acid (HBr):

The molar mass of HBr is approximately 80.91 g/mol.

Mass = 4.01e-3 mol x 80.91 g/mol = 0.3247 g

So, the mass of each sample is as follows:

188.86 grams of aluminum

6.16e-14 grams of carbon dioxide

6.59e-10 grams of sodium nitrate

0.1256 grams of C2H6O

2.43e-7 grams of uranium

0.3247 grams of hydrobromic acid.