1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).
MM Co(C2H3O2)2: 177.02g (anhydrate)
+ MM 4H2O: 72.06g (water)
MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)
2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).
72.06g
249.08g x 100%
Percent water of hydrate is 28.93%.
Finding Molar Mass
# atoms Element A * Atomic Mass Element A = Mass A
# atoms Element B * Atomic Mass Element B = Mass B
... etc.
Add up all of the mass values and you have the molar mass of the substance.
Mn(CH3COO)2 4H2O
hydrochloric acid
The formula for nickel II sulfate tetrahydrate is NiSO4 * 4H2O.
5048+w4g5=23vm32
Nope, combustion
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
2SnCl4 + 4H2O = 8HCl + Sn2O4
Water and Carbon dioxide. Here is the Balanced combustion eq'n. CH3CH2CH3 + 5O2 = 4H2O + 3CO2
4 molecules It's Na2CrO4 · 4H2O
The answer is: C3H8 + 5O2 3CO2 + 4H2O
C3h8 + 5o2 -----> 3co2 + 4h2o
It depends upon the extent of combustion take propane as an example Complete Combustion: C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l) Incomplete Combustion: C3H8(g) + 3.5O2(g) --> 3CO(g) + 4H2O(l) Very Incomplete Combustion: C3H8(g) + 2O2(g) --> 3C(s) + 4H2O(l) Products of Complete = Carbon Dioxide + Water Products of Incomplete = Carbon Monoxide + Water Products of Very Incomplete = Amorphous Carbon (soot) + Water
2NH4NO3->2N2+O2+4H2O
2ch4 + 3o2 ==> 2c2o + 4h2o
it is combustion reaction, thus will produce water and carbon dioxide. C3H8 + 5O2 --> 3CO2 +4H2O
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
Mn(CH3COO)2 4H2O